Voltage calcs.Testatika correl.
Exp.2-Chg. test (100514)
EV Gray tube
Hans Coler's devices
Roy Meyers device
SMOT mark 1
Water Wheel Mag. Motor
The calculations on this page are no longer valid. They sum the amplitudes of the waves when they should have been summing the square of the amplitudes. While this may seem like an easy change, it isn't. Hopefully some way will be found in the future to produce new calculations.
The purpose of this voltage is to pull electrons to either side of each of the meshes that are the output cylinders. This is to surround the holes in the meshes with electrons with the intent of creating new charged particles within the holes as per this theory. The number of electrons needed surrounding the holes has already been calculated here. Here is a repeat of the initial illustration from that page.
So as the small diagram to the right above shows, e represents the length of the side of a hole, including the surrounding wire (e.g. e=0.000294m).
From the previous calculations for electrons in a circle the number of electrons needed on the wire around our mesh hole to produce an electrons in the center of the hole is calculated using this formula:
where e/2 is the radius of the electron circle or half the width of the mesh hole and surrounding wire.
We then divide by the number of electrons needed around a hole by 4 since we want the number per side.
The basic layout of the device with the outer cylindrical electrode, one output mesh cylinder and the inner cylindrical electrode looks like this.
We next need to find out the number of electrons needed for all the holes in an output cylinder made of the above mesh. That isn't simply the number of holes multiplied by the number of electrons needed per hole. That's because each hole shares electrons with its neighbor holes. So we really need to know how many individual hole sides there are, taking into account that the four sides to any hole are shared by its neighbor sides.
The number of holes in a single line lengthwise is L/e (187, rounding down) and the number of holes in a single circumference is 2πo/e (288). The number of hole sides in all lines lengthwise is therefore:
And the number of hole sides in all circumferences is:
So finally the total number of electrons needed for all sides is:
We now know how many electrons we need to spread out on the mesh so that we have the proper number surrounding each hole in order to create an electron in the center of each hole.
Next we need to find out what voltage is needed across the inner and outer cylindrical electrodes in order to get those electrons to the mesh. The following diagram illustrates that the number of electrons we need on a mesh is also the number of electrons we need on a nearby electrode, 1.02781426x1013 electrons.
We can use this number of electrons to find the voltage that we need to put across the electrodes in order to get those electrons onto the mesh, starting with finding the capacitance. The capacitance of a cylindrical capacitor is:
We also know that capacitance is a ratio of the charge to the voltage, which by rearranging as follows gives us the formula for the voltage.
Calculating it out we get:
This sounds quite high but by playing around with the variables, substituting reasonable variables into a spreadsheet then something lower such as the 32kV below can be arrived at.
The above is for a 6cm long cylindrical capacitor, with the same mesh size used on the page above, but with a 1/4" diameter rod (0.003175m radius) for the inner cylinder electrode, a 6mm gap between the inner cylinder and the output cylinder where this gap is filled with a high dielectric constant (K=15) mix of Barium Titanate (BaTiO3) and epoxy, and the outer cylinder has a radius of 12mm.
The above can also be improved with a higher dielectric constant (K) though from experience, that is difficult to achieve in a home workshop. Also, the dielectric material can easily be made one or two millimeters thinner, though again based on experience, not much more than that.
If sharp voltage spikes are used then supplying this high voltage while not having dielectric breakdown issues is not that difficult.
Also, an assumption is being made here that the electrons in the circle, or on the sides of the mesh holes, will be the sole supply of waves to make up the required amplitude at the center of the circle. In fact, a contribution will also be made by all other surrounding electrons. Without their contribution there would be no net gain in energy. As a result, the required voltage may be much smaller.